韩信点兵是一道古代数学题，内容是：韩信带兵不足百人，三人一行排列多一个，七人一行排列少两个，五人一行排列正好。相关代码：
int a = 0, b = 0, c = 0;//定义变量
for (int i = 1; i < 100; i++)//遍历
{
Math.DivRem(i, 3, out a);//3行一列时取余
Math.DivRem(i, 5, out b);//5行一列时取余
Math.DivRem(i, 7, out c);//7行一列时取余
if (a == 1 && b == 0 && c == 5)//如果3种方式的余数符合要求
{
textBox1.Text = i.ToString();//显示人数
return;
}
SHOW FULL COLUMNS FROM `jrk_downrecords` [ RunTime:0.001314s ]
SELECT `a`.`aid`,`a`.`title`,`a`.`create_time`,`m`.`username` FROM `jrk_downrecords` `a` INNER JOIN `jrk_member` `m` ON `a`.`uid`=`m`.`id` WHERE `a`.`status` = 1 GROUP BY `a`.`aid` ORDER BY `a`.`create_time` DESC LIMIT 10 [ RunTime:0.097566s ]
SHOW FULL COLUMNS FROM `jrk_tagrecords` [ RunTime:0.001146s ]
SELECT * FROM `jrk_tagrecords` WHERE `status` = 1 ORDER BY `num` DESC LIMIT 20 [ RunTime:0.001888s ]
SHOW FULL COLUMNS FROM `jrk_member` [ RunTime:0.001148s ]
SELECT `id`,`username`,`userhead`,`usertime` FROM `jrk_member` WHERE `status` = 1 ORDER BY `usertime` DESC LIMIT 10 [ RunTime:0.003670s ]
SHOW FULL COLUMNS FROM `jrk_searchrecords` [ RunTime:0.001001s ]
SELECT * FROM `jrk_searchrecords` WHERE `status` = 1 ORDER BY `num` DESC LIMIT 5 [ RunTime:0.003295s ]
SELECT aid,title,count(aid) as c FROM `jrk_downrecords` GROUP BY `aid` ORDER BY `c` DESC LIMIT 10 [ RunTime:0.015149s ]
SHOW FULL COLUMNS FROM `jrk_articles` [ RunTime:0.001364s ]
UPDATE `jrk_articles` SET `hits` = 1 WHERE `id` = 75058 [ RunTime:0.001685s ]
