实现阶乘计算。。。
function numberFactorial(n:Number):Number {
var a:Number=1;
var b:Number;
if (n<=0) {
trace("Please entry a positive integer!!");
//break;
} else {
for (var i:Number=1; i<=n; i++) {
a*=i;
}
b=a;
SHOW FULL COLUMNS FROM `jrk_downrecords` [ RunTime:0.001386s ]
SELECT `a`.`aid`,`a`.`title`,`a`.`create_time`,`m`.`username` FROM `jrk_downrecords` `a` INNER JOIN `jrk_member` `m` ON `a`.`uid`=`m`.`id` WHERE `a`.`status` = 1 GROUP BY `a`.`aid` ORDER BY `a`.`create_time` DESC LIMIT 10 [ RunTime:0.095312s ]
SHOW FULL COLUMNS FROM `jrk_tagrecords` [ RunTime:0.001265s ]
SELECT * FROM `jrk_tagrecords` WHERE `status` = 1 ORDER BY `num` DESC LIMIT 20 [ RunTime:0.001986s ]
SHOW FULL COLUMNS FROM `jrk_member` [ RunTime:0.001266s ]
SELECT `id`,`username`,`userhead`,`usertime` FROM `jrk_member` WHERE `status` = 1 ORDER BY `usertime` DESC LIMIT 10 [ RunTime:0.003764s ]
SHOW FULL COLUMNS FROM `jrk_searchrecords` [ RunTime:0.001118s ]
SELECT * FROM `jrk_searchrecords` WHERE `status` = 1 ORDER BY `num` DESC LIMIT 5 [ RunTime:0.003330s ]
SELECT aid,title,count(aid) as c FROM `jrk_downrecords` GROUP BY `aid` ORDER BY `c` DESC LIMIT 10 [ RunTime:0.016769s ]
SHOW FULL COLUMNS FROM `jrk_articles` [ RunTime:0.001948s ]
UPDATE `jrk_articles` SET `hits` = 1 WHERE `id` = 281738 [ RunTime:0.001510s ]