01背包问题最简单实现，可在其上做更多的扩展，不知道可否不用递归用堆栈-01 knapsack problem to achieve the most simple, can do more in its expansion, I do not know can not use recursive stack
SHOW FULL COLUMNS FROM `jrk_downrecords` [ RunTime:0.001505s ]
SELECT `a`.`aid`,`a`.`title`,`a`.`create_time`,`m`.`username` FROM `jrk_downrecords` `a` INNER JOIN `jrk_member` `m` ON `a`.`uid`=`m`.`id` WHERE `a`.`status` = 1 GROUP BY `a`.`aid` ORDER BY `a`.`create_time` DESC LIMIT 10 [ RunTime:0.109590s ]
SHOW FULL COLUMNS FROM `jrk_tagrecords` [ RunTime:0.001337s ]
SELECT * FROM `jrk_tagrecords` WHERE `status` = 1 ORDER BY `num` DESC LIMIT 20 [ RunTime:0.002309s ]
SHOW FULL COLUMNS FROM `jrk_member` [ RunTime:0.001421s ]
SELECT `id`,`username`,`userhead`,`usertime` FROM `jrk_member` WHERE `status` = 1 ORDER BY `usertime` DESC LIMIT 10 [ RunTime:0.004538s ]
SHOW FULL COLUMNS FROM `jrk_searchrecords` [ RunTime:0.001243s ]
SELECT * FROM `jrk_searchrecords` WHERE `status` = 1 ORDER BY `num` DESC LIMIT 5 [ RunTime:0.003998s ]
SELECT aid,title,count(aid) as c FROM `jrk_downrecords` GROUP BY `aid` ORDER BY `c` DESC LIMIT 10 [ RunTime:0.019337s ]
SHOW FULL COLUMNS FROM `jrk_articles` [ RunTime:0.001904s ]
UPDATE `jrk_articles` SET `hits` = 1 WHERE `id` = 222517 [ RunTime:0.001362s ]
