在0和1情况下进行背包问题解决,涉及多个物体的重量和价值,求得最大价值量以及分配方案。-At 0 and 1 backpack case for problem-solving, involving more than the weight of objects and values, as well as to achieve maximum value distribution program.
SHOW FULL COLUMNS FROM `jrk_downrecords` [ RunTime:0.002158s ]
SELECT `a`.`aid`,`a`.`title`,`a`.`create_time`,`m`.`username` FROM `jrk_downrecords` `a` INNER JOIN `jrk_member` `m` ON `a`.`uid`=`m`.`id` WHERE `a`.`status` = 1 GROUP BY `a`.`aid` ORDER BY `a`.`create_time` DESC LIMIT 10 [ RunTime:0.085468s ]
SHOW FULL COLUMNS FROM `jrk_tagrecords` [ RunTime:0.002421s ]
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SHOW FULL COLUMNS FROM `jrk_member` [ RunTime:0.002319s ]
SELECT `id`,`username`,`userhead`,`usertime` FROM `jrk_member` WHERE `status` = 1 ORDER BY `usertime` DESC LIMIT 10 [ RunTime:0.003651s ]
SHOW FULL COLUMNS FROM `jrk_searchrecords` [ RunTime:0.001980s ]
SELECT * FROM `jrk_searchrecords` WHERE `status` = 1 ORDER BY `num` DESC LIMIT 5 [ RunTime:0.003263s ]
SELECT aid,title,count(aid) as c FROM `jrk_downrecords` GROUP BY `aid` ORDER BY `c` DESC LIMIT 10 [ RunTime:0.015193s ]
SHOW FULL COLUMNS FROM `jrk_articles` [ RunTime:0.003221s ]
UPDATE `jrk_articles` SET `hits` = 1 WHERE `id` = 152412 [ RunTime:0.001167s ]