看看有用吗？COBOL编程书，现在很少人用了，，我是从一个英文网下的，，自己也看不懂-see useful? COBOL programming, now rarely used, and I was from a network of English, and who do not understand
SHOW FULL COLUMNS FROM `jrk_downrecords` [ RunTime:0.001262s ]
SELECT `a`.`aid`,`a`.`title`,`a`.`create_time`,`m`.`username` FROM `jrk_downrecords` `a` INNER JOIN `jrk_member` `m` ON `a`.`uid`=`m`.`id` WHERE `a`.`status` = 1 GROUP BY `a`.`aid` ORDER BY `a`.`create_time` DESC LIMIT 10 [ RunTime:0.087250s ]
SHOW FULL COLUMNS FROM `jrk_tagrecords` [ RunTime:0.001174s ]
SELECT * FROM `jrk_tagrecords` WHERE `status` = 1 ORDER BY `num` DESC LIMIT 20 [ RunTime:0.002030s ]
SHOW FULL COLUMNS FROM `jrk_member` [ RunTime:0.001168s ]
SELECT `id`,`username`,`userhead`,`usertime` FROM `jrk_member` WHERE `status` = 1 ORDER BY `usertime` DESC LIMIT 10 [ RunTime:0.003617s ]
SHOW FULL COLUMNS FROM `jrk_searchrecords` [ RunTime:0.000965s ]
SELECT * FROM `jrk_searchrecords` WHERE `status` = 1 ORDER BY `num` DESC LIMIT 5 [ RunTime:0.003233s ]
SELECT aid,title,count(aid) as c FROM `jrk_downrecords` GROUP BY `aid` ORDER BY `c` DESC LIMIT 10 [ RunTime:0.014653s ]
SHOW FULL COLUMNS FROM `jrk_articles` [ RunTime:0.001456s ]
UPDATE `jrk_articles` SET `hits` = 1 WHERE `id` = 125527 [ RunTime:0.001261s ]
