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经典c程序100例==1--10 【程序1】 题目：有1、2、3、4个数字，能组成多少个互不相同且无重复数字的三位数？都是多少？ 1.程序分析：可填在百位、十位、个位的数字都是1、2、3、4。组成所有的排列后再去 掉不满足条件的排列。 2.程序源代码： main() { int i,j,k printf("
") for(i=1 i<5 i++) ／*以下为三重循环*/ for(j=1 j<5 j++) for (k=1 k<5 k++) { if (i!=k&&i!=j&&j!=k) /*确保i、j、k三位互不相同*/ printf("%d,%d,%d
",i,j,k) }-classic procedures hundred cases == 1-- 10 procedures-- a topic : 1,2,3,4 figures, the number can be formed with each other with no repeat of the triple-digit figures? How many are? 1. Program Analysis : can fill the 100, 10, 000 the number of spaces are 1,2,3,4. With all the components removed after not satisfied with the conditions. 2. Source code : main () (int i, j, k printf ( " n") for (i = 1 ilt; 5 i)/* the following as the triple cycle*/for (j = 1 JLT; 5 j) for (k = 1 KLT; 5 k) (if (i! = ki! = jj! = k)/* i, j, k three disparate*/printf ( "% d,% d,% d n ", i, j, k
